Solve the following pair of linear equations | vedclass

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(A) Given equations are:$1) 5x - 3y = 1$$2) 2x + 5y = 19$From equation $(1)$,we get $5x = 1 + 3y$,so $x = \frac{1 + 3y}{5}$.Substitute this value of $

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$x = 2, y = 3$

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(A) Given equations are:$1) 5x - 3y = 1$$2) 2x + 5y = 19$From equation $(1)$,we get $5x = 1 + 3y$,so $x = \frac{1 + 3y}{5}$.Substitute this value of $x$ into equation $(2)$:$2(\frac{1 + 3y}{5}) + 5y = 19$Multiply by $5$ to clear the denominator:$2(1 + 3y) + 25y = 95$$2 + 6y + 25y = 95$$31y = 93$$y = 3$Now,substitute $y = 3$ back into the expression for $x$:$x = \frac{1 + 3(3)}{5} = \frac{1 + 9}{5} = \frac{10}{5} = 2$.Thus,the solution is $(x, y) = (2, 3)$.

Solve the following pair of linear equations by the method of substitution: $5x - 3y = 1$ and $2x + 5y = 19$.

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